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$lastN
New in version 5.2.在版本5.2中新增。
Returns a specified number of elements from the end of an array.从数组末尾返回指定数量的元素。
$lastN
has the following syntax:语法如下:
{ $lastN: { n: <expression>, input: <expression> } }
n | $lastN returns.$lastN 返回的数组元素数。
|
input | n elements.n 个元素的数组的表达式。
|
$lastN
$lastN
null
values in the input array.null
值。n
less than 1
.n
小于1
的值。n
is greater than or equal to the number of elements in the input
array, $lastN
returns the input
array.n
大于或等于input
数组中的元素数,$lastN
将返回input
数组。input
resolves to a non-array value, the aggregation operation errors.input
解析为非数组值,则聚合操作出错。The collection 集合games
has the following documents:games
有以下文档:
db.games.insertMany([ { "playerId" : 1, "score" : [ 1, 2, 3 ] }, { "playerId" : 2, "score" : [ 12, 90, 7, 89, 8 ] }, { "playerId" : 3, "score" : [ null ] }, { "playerId" : 4, "score" : [ ] }, { "playerId" : 5, "score" : [ 1293, null, 3489, 9 ]}, { "playerId" : 6, "score" : [ "12.1", 2, NumberLong("2090845886852"), 23 ]} ])
The following example uses the 下面的示例使用$lastN
operator to retrieve the last three scores for each player. $lastN
运算符检索每个玩家的最后三个分数。The scores are returned in the new field 分数将返回到lastScores
created by $addFields
.$addFields
创建的新字段lastScores
中。
db.games.aggregate([ { $addFields: { lastScores: { $lastN: { n: 3, input: "$score" } } } } ])
The operation returns the following results:该操作返回以下结果:
[{ "playerId": 1, "score": [ 1, 2, 3 ], "lastScores": [ 1, 2, 3 ] }, { "playerId": 2, "score": [ 12, 90, 7, 89, 8 ], "lastScores": [ 7, 89, 8 ] }, { "playerId": 3, "score": [ null ], "lastScores": [ null ] }, { "playerId": 4, "score": [ ], "lastScores": [ ] }, { "playerId": 5, "score": [ 1293, null, 3489, 9 ], "lastScores": [ null, 3489, 9 ] }, { "playerId": 6, "score": [ "12.1", 2, NumberLong("2090845886852"), 23 ], "lastScores": [ 2, NumberLong("2090845886852"), 23 ] }]