$top (aggregation accumulator)
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Definition
Syntax
{
$top:
{
sortBy: { <field1>: <sort order>, <field2>: <sort order> ... },
output: <expression>
}
}| Field | Necessity | Description |
|---|---|---|
| sortBy | Required | Specifies the order of results, with syntax similar to $sort. |
| output | Required | Represents the output for each element in the group and can be any expression. |
Behavior
Null and Missing Values
Consider the following aggregation that returns the top document from a group of scores:
-
$topdoes not filter out null values. -
$topconverts missing values to null.
db.aggregate( [ { $documents: [ { playerId: "PlayerA", gameId: "G1", score: 1 }, { playerId: "PlayerB", gameId: "G1", score: 2 }, { playerId: "PlayerC", gameId: "G1", score: 3 }, { playerId: "PlayerD", gameId: "G1"}, { playerId: "PlayerE", gameId: "G1", score: null } ] }, { $group: { _id: "$gameId", playerId: { $top: { output: [ "$playerId", "$score" ], sortBy: { "score": 1 } } } } } ] )
In this example:
-
$documentscreates the literal documents that contain player scores. -
$groupgroups the documents bygameId. This example has only onegameId,G1. -
PlayerDhas a missing score andPlayerEhas a nullscore. These values are both considered as null. -
The
playerIdandscorefields are specified asoutput : ["$playerId"," $score"]and returned as array values. -
Specify the sort order with
sortBy: { "score": 1 }. -
PlayerDandPlayerEtied for the top element.PlayerDis returned as the topscore. -
To have more deterministic tie breaking behavior for multiple null values, add more fields to``sortBy``.
[
{
_id: 'G1',
playerId: [ [ 'PlayerD', null ] ]
}
]Restrictions
Window Function and Aggregation Expression Support
$top is not supported as a aggregation expression.
$top is supported as a window operator.
Memory Limit Considerations
Aggregation pipelines which call $top are subject to the 100 MB limit. If this limit is exceeded for an individual group, the aggregation fails with an error.
Examples
Consider a gamescores collection with the following documents:
db.gamescores.insertMany([ { playerId: "PlayerA", gameId: "G1", score: 31 }, { playerId: "PlayerB", gameId: "G1", score: 33 }, { playerId: "PlayerC", gameId: "G1", score: 99 }, { playerId: "PlayerD", gameId: "G1", score: 1 }, { playerId: "PlayerA", gameId: "G2", score: 10 }, { playerId: "PlayerB", gameId: "G2", score: 14 }, { playerId: "PlayerC", gameId: "G2", score: 66 }, { playerId: "PlayerD", gameId: "G2", score: 80 } ])
Find the Top Score
You can use the $top accumulator to find the top score in a single game.
db.gamescores.aggregate( [ { $match : { gameId : "G1" } }, { $group: { _id: "$gameId", playerId: { $top: { output: [ "$playerId", "$score" ], sortBy: { "score": -1 } } } } } ] )
The example pipeline:
-
Uses
$matchto filter the results on a singlegameId. In this case,G1. -
Uses
$groupto group the results bygameId. In this case,G1. -
Specifies the fields that are output for
$topwithoutput : ["$playerId"," $score"]. -
Uses
sortBy: { "score": -1 }to sort the scores in descending order. -
Uses
$topto return the top score in the game.
The operation returns the following results:
[ { _id: 'G1', playerId: [ 'PlayerC', 99 ] } ]Find the Top Score Across Multiple Games
You can use the $top accumulator to find the top score in each game.
db.gamescores.aggregate( [ { $group: { _id: "$gameId", playerId: { $top: { output: [ "$playerId", "$score" ], sortBy: { "score": -1 } } } } } ] )
The example pipeline:
-
Uses
$groupto group the results bygameId. -
Uses
$topto return topscorefor each game. -
Specifies the fields that are output for
$topwithoutput : ["$playerId", "$score"]. -
Uses
sortBy: { "score": -1 }to sort the scores in descending order.
The operation returns the following results:
[
{ _id: 'G2', playerId: [ 'PlayerD', 80 ] },
{ _id: 'G1', playerId: [ 'PlayerC', 99 ] }
]