$lastN (array operator)
On this page本页内容
Definition定义
$lastNNew in version 5.2.5.2版新增。Returns a specified number of elements from the end of an array.从数组末尾返回指定数量的元素。
Tip
See also: 另请参阅:
Syntax语法
$lastN has the following syntax:具有以下语法:
{ $lastN: { n: <expression>, input: <expression> } }
n | $lastN returns.$lastN返回的数组元素数。 |
input | n elements.n个元素的数组的表达式。 |
Behavior行为
$lastNreturns elements in the same order they appear in the input array.按元素在输入数组中出现的相同顺序返回元素。$lastNdoes not filter out不会筛选掉输入数组中的nullvalues in the input array.null值。You cannot specify a value of不能指定小于nless than1.1的n值。If the specified如果指定的nis greater than or equal to the number of elements in theinputarray,$lastNreturns theinputarray.n大于或等于input数组中的元素数,$lastN将返回input数组。If如inputresolves to a non-array value, the aggregation operation errors.input解析为非数组值,则聚合操作将出错。
Example实例
The collection 集合games has the following documents:games有以下文档:
db.games.insertMany([
{ "playerId" : 1, "score" : [ 1, 2, 3 ] },
{ "playerId" : 2, "score" : [ 12, 90, 7, 89, 8 ] },
{ "playerId" : 3, "score" : [ null ] },
{ "playerId" : 4, "score" : [ ] },
{ "playerId" : 5, "score" : [ 1293, null, 3489, 9 ]},
{ "playerId" : 6, "score" : [ "12.1", 2, NumberLong("2090845886852"), 23 ]}
])
The following example uses the 以下示例使用$lastN operator to retrieve the last three scores for each player. $lastN运算符来检索每个玩家的最后三个分数。The scores are returned in the new field 分数在lastScores created by $addFields.$addFields创建的新字段lastScores中返回。
db.games.aggregate([
{ $addFields: { lastScores: { $lastN: { n: 3, input: "$score" } } } }
])
The operation returns the following results:该操作返回以下结果:
[{
"playerId": 1,
"score": [ 1, 2, 3 ],
"lastScores": [ 1, 2, 3 ]
},
{
"playerId": 2,
"score": [ 12, 90, 7, 89, 8 ],
"lastScores": [ 7, 89, 8 ]
},
{
"playerId": 3,
"score": [ null ],
"lastScores": [ null ]
},
{
"playerId": 4,
"score": [ ],
"lastScores": [ ]
},
{
"playerId": 5,
"score": [ 1293, null, 3489, 9 ],
"lastScores": [ null, 3489, 9 ]
},
{
"playerId": 6,
"score": [ "12.1", 2, NumberLong("2090845886852"), 23 ],
"lastScores": [ 2, NumberLong("2090845886852"), 23 ]
}]