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$top (aggregation accumulator)

Definition定义

$top

New in version 5.2. 5.2版新增。

Returns the top element within a group according to the specified sort order.根据指定的排序顺序返回组中的顶部元素。

Syntax语法

{
$top:
{
sortBy: { <field1>: <sort order>, <field2>: <sort order> ... },
output: <expression>
}
}
Field字段Necessity必要性Description描述
sortByRequired必要的Specifies the order of results, with syntax similar to $sort.指定结果的顺序,语法类似于$sort
outputRequired必要的Represents the output for each element in the group and can be any expression.表示组中每个元素的输出,可以是任何表达式。

Behavior行为

Null and Missing ValuesNull值和缺失值

Consider the following aggregation that returns the top document from a group of scores:考虑以下聚合,该聚合从一组分数中返回排名靠前的文档:

  • $top does not filter out null values.不筛选空值。
  • $top converts missing values to null.将缺少的值转换为null
db.aggregate( [
{
$documents: [
{ playerId: "PlayerA", gameId: "G1", score: 1 },
{ playerId: "PlayerB", gameId: "G1", score: 2 },
{ playerId: "PlayerC", gameId: "G1", score: 3 },
{ playerId: "PlayerD", gameId: "G1"},
{ playerId: "PlayerE", gameId: "G1", score: null }
]
},
{
$group:
{
_id: "$gameId",
playerId:
{
$top:
{
output: [ "$playerId", "$score" ],
sortBy: { "score": 1 }
}
}
}
}
] )

In this example:在本例中:

  • $documents creates the literal documents that contain player scores.创建包含玩家分数的文字文档。
  • $group groups the documents by gameId. gameId对文档进行分组。This example has only one gameId, G1.这个例子只有一个gameIdG1
  • PlayerD has a missing score and PlayerE has a null score. PlayerDscore缺失,PlayerEscore为空。These values are both considered as null.这两个值都被视为null
  • The playerId and score fields are specified as output : ["$playerId"," $score"] and returned as array values.playerIdscore字段被指定为output : ["$playerId"," $score"],并作为数组值返回。
  • Specify the sort order with sortBy: { "score": 1 }.使用sortBy: { "score": 1 }指定排序顺序。
  • PlayerD and PlayerE tied for the top element. PlayerDPlayerE并列第一。PlayerD is returned as the top score.PlayerD作为最高分数返回。
  • To have more deterministic tie breaking behavior for multiple null values, add more fields to``sortBy``.若要为多个null值提供更具确定性的平局打破行为,请在sortBy中添加更多字段。
[
{
_id: 'G1',
playerId: [ [ 'PlayerD', null ] ]
}
]

Restrictions限制

Window Function and Aggregation Expression Support窗口函数和聚合表达式支持

$top is not supported as a aggregation expression.$top不支持作为聚合表达式

$top is supported as a window operator.$top被支持作为窗口运算符

Memory Limit Considerations内存限制注意事项

Aggregation pipelines which call $top are subject to the 100 MB limit. 调用$top的聚合管道受100MB限制If this limit is exceeded for an individual group, the aggregation fails with an error.如果单个组超过此限制,则聚合将失败并出现错误。

Examples实例

Consider a gamescores collection with the following documents:考虑一个包含以下文档的gamescores集合:

db.gamescores.insertMany([
{ playerId: "PlayerA", gameId: "G1", score: 31 },
{ playerId: "PlayerB", gameId: "G1", score: 33 },
{ playerId: "PlayerC", gameId: "G1", score: 99 },
{ playerId: "PlayerD", gameId: "G1", score: 1 },
{ playerId: "PlayerA", gameId: "G2", score: 10 },
{ playerId: "PlayerB", gameId: "G2", score: 14 },
{ playerId: "PlayerC", gameId: "G2", score: 66 },
{ playerId: "PlayerD", gameId: "G2", score: 80 }
])

Find the Top Score查找最高分

You can use the $top accumulator to find the top score in a single game.您可以使用$top累加器来查找单场比赛的最高分数。

db.gamescores.aggregate( [
{
$match : { gameId : "G1" }
},
{
$group:
{
_id: "$gameId",
playerId:
{
$top:
{
output: [ "$playerId", "$score" ],
sortBy: { "score": -1 }
}
}
}
}
] )

The example pipeline:示例管道:

  • Uses $match to filter the results on a single gameId. In this case, G1.使用$match筛选单个gameId的结果。在这种情况下,G1
  • Uses $group to group the results by gameId. In this case, G1.使用$groupgameId对结果进行分组。在这种情况下,G1
  • Specifies the fields that are output for $top with output : ["$playerId"," $score"].指定$top的输出字段,使用output : ["$playerId"," $score"]
  • Uses sortBy: { "score": -1 } to sort the scores in descending order.使用sortBy: { "score": -1 }按降序对分数进行排序。
  • Uses $top to return the top score in the game.使用$top返回游戏中的最高分数。

The operation returns the following results:该操作返回以下结果:

[ { _id: 'G1', playerId: [ 'PlayerC', 99 ] } ]

Find the Top Score Across Multiple Games在多个游戏中查找最高分

You can use the $top accumulator to find the top score in each game.您可以使用$top累加器来查找每场比赛的最高分数。

db.gamescores.aggregate( [
{
$group:
{ _id: "$gameId", playerId:
{
$top:
{
output: [ "$playerId", "$score" ],
sortBy: { "score": -1 }
}
}
}
}
] )

The example pipeline:示例管道:

  • Uses $group to group the results by gameId.使用$groupgameId对结果进行分组。
  • Uses $top to return top score for each game.使用$top返回每场比赛的最高分数。
  • Specifies the fields that are output for $top with output : ["$playerId", "$score"].指定$top的输出字段,使用output : ["$playerId", "$score"]
  • Uses sortBy: { "score": -1 } to sort the scores in descending order.使用sortBy: { "score": -1 }按降序对分数进行排序。

The operation returns the following results:该操作返回以下结果:

[
{ _id: 'G2', playerId: [ 'PlayerD', 80 ] },
{ _id: 'G1', playerId: [ 'PlayerC', 99 ] }
]